Yes, the selection is random. With a sample of only
four destinations, you should not expect a perfect
distribution. If you increase the number of routes
gbeing advertised to several hundred, you will see a
more nearly equal distribution.
-----Original Message-----
From: Andrew Smith [mailto:as160@yahoo.com]
Sent: Tuesday, October 23, 2001 12:16 AM
To: juniper-nsp@puck.nether.net
Subject: Per packet load balancing -- 2nd try
Hi, all
I will try to ask this questions again and hope some
get some expert advice on this topic.
What I have is the following, all boxes have IP2. I
have per-packet load balancing configured.
----
M40 ---- M20 (advertising 1.0.0.0/24
---- 1.0.1.0/24
---- 1.0.2.0/24
1.0.3.0/24)
4 paths between M40 and M20 are equal cost. M20 is
advertising 4 destinations via OSPF to M40. What I've
seen on M40's routing table is:
1.0.0.0/24 via path 1
via path 2
via path 3
>via path 4
1.0.0.0/24 via path 1
via path 2
via path 3
>via path 4
1.0.0.0/24 via path 1
via path 2
>via path 3
via path 4
1.0.0.0/24 via path 1
via path 2
>via path 3
via path 4
So, how is the next-hop selected? randomly? In this
case, why are the other 2 paths not being utilized?
I turned on trace options for OSPF, but couldn't
really extract the info I need.
TIA for any pointers.
---andrew
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