Input vs. Output EXAMPLE CORRECTED

[GPBATEY]

In my first message I worked my example incorrectly.  
The corrected version is here:

there fore if

Power Forward = 100 watts

and

Power Reflected = 5 watts

p= SQRT ( 5/100)  = SQRT(0.05) = 0.223

and then

VSWR= (1 + 0.223) / (1 - 0.223) = 1.223/.776 =1.57 

thus the SWR is 1.57 to 1

====================================================
Orginal Message text written by GPBATEY
>
Mel

Most any handbook will have the info.  The following is from the 
1988 ARRL handbook, page 16-2.

VSWR = (1 + p) / (1 - p)

where 

p = SQRT (Power reflected/ Power Forward)

and SQRT is Square Root

there fore if

Power Forward = 100 watts

and

Power Reflected = 5 watts

p= SQRT ( 100/5)  = SQRT(20) = 4.47

and then

VSWR= (1 + 4.47) / (1 - 4.47) = 5.47/-3.47 = -1.57 

The minus sign is neglected.

thus the SWR is 1.57 to 1

Hope that this helps.

73 Gordon WA4FJC<

-----------------------------------------------------------
Products bought, sold or traded here is the responsibility of the
parties involved.  This list and the City of Tempe are not responsible
for losses or misrepresentations of any kind.  Buyer beware!

-----------------------------------------------------------
This list is a public service of the City of Tempe, Arizona
-----------------------------------------------------------

Subscription control - http://www.tempe.gov/lists/control.asp?list=HEATH
To post - HEATH at LISTSERV.TEMPE.GOV
Archives - http://listserv.tempe.gov/archives/HEATH.html