[From nobody Mon Jan 10 18:47:51 2011 From: "k5cr@juno.com" <k5cr@juno.com> To: "john.clark@STATE.CO.US" <john.clark@STATE.CO.US> Subject: Re: FW: HW-101 step 4 Date: Tue, 11 May 1999 09:30:06 -0600 MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit John: I see you have received a couple of replies on your oscillator question. I will give you a little theory. As you peak the oscillator (using a VTVM to monitor the grid voltage) you will get a higher negative voltage the as the plate tank circuit is tuned to resonance. (Oscillator run in Class C so there is grid current that inturn drives the grid more negative). On one side of resonance you will find the grid voltage has a nice gradual peak, while the other side of resonance the tuning is sharper and falls off rapidly. The higher grid voltage relates to a higher RF output voltage from the plate circuit. The goal here is to get the highest output from the oscillator. However, you don't want to peak the plate tank circuit and leave it tuned to the peak. You want to peak the tank circuit but back off (on the slow peaking side of resonance) to about 80 to 90 percent of the peak grid voltage. The reason for not leaving the oscillator tuned to the peak is you want the oscillator to start oscillating each time it is turned on. If you peak the adjustment there is a good chance with aging the oscillator won't start or it will quit oscillating when loaded. I hope this helps answer your question. 73 Doug/K5CR ___________________________________________________________________ You don't need to buy Internet access to use free Internet e-mail. Get completely free e-mail from Juno at http://www.juno.com/getjuno.html or call Juno at (800) 654-JUNO [654-5866] ]