Yes, but if per packet load balancing is NOT enabled, the distribution
is random among equal cost links as was suggested by Paul.
-- steve
> -----Original Message-----
> From: Guy Davies [mailto:Guy.Davies@telindus.co.uk]
> Sent: Tuesday, October 23, 2001 3:24 AM
> To: 'Andrew Smith'; 'juniper-nsp@puck.nether.net'
> Subject: RE: Per packet load balancing -- 2nd try
>
>
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> Hi Andrew,
>
> There's a pretty good explanation of the behaviour on Juniper's
> website. Just go to http://www.juniper.net/ and put "per packet load
> balancing" in the search pane.
>
> The Generic Routing Config pdf has a good explanation at
> http://www.juniper.net/techpubs/software/junos50/swconfig50-routing/do
> wnload/routing-generic-config.pdf
>
> In short, the behaviour differs based on whether you use an IP I or
> an IP II.
>
> With an IP I, you get what I would consider true per packet load
> sharing... i.e. packets are placed onto each path in a round-robin
> basis.
>
> With an IP II, you get something more like per-flow load sharing...
> i.e. each new flow is randomly associated with a next-hop and, until
> there is a routing update, it persists with that next-hop.
>
> Regards,
>
> Guy
>
> > -----Original Message-----
> > From: Andrew Smith [mailto:as160@yahoo.com]
> > Sent: Tuesday, October 23, 2001 8:16 AM
> > To: juniper-nsp@puck.nether.net
> > Subject: Per packet load balancing -- 2nd try
> >
> >
> > Hi, all
> >
> > I will try to ask this questions again and hope some
> > get some expert advice on this topic.
> >
> > What I have is the following, all boxes have IP2. I
> > have per-packet load balancing configured.
> >
> > ----
> > M40 ---- M20 (advertising 1.0.0.0/24
> > ---- 1.0.1.0/24
> > ---- 1.0.2.0/24
> > 1.0.3.0/24)
> >
> > 4 paths between M40 and M20 are equal cost. M20 is
> > advertising 4 destinations via OSPF to M40. What I've
> > seen on M40's routing table is:
> >
> > 1.0.0.0/24 via path 1
> > via path 2
> > via path 3
> > >via path 4
> >
> > 1.0.0.0/24 via path 1
> > via path 2
> > via path 3
> > >via path 4
> >
> > 1.0.0.0/24 via path 1
> > via path 2
> > >via path 3
> > via path 4
> >
> > 1.0.0.0/24 via path 1
> > via path 2
> > >via path 3
> > via path 4
> >
> > So, how is the next-hop selected? randomly? In this
> > case, why are the other 2 paths not being utilized?
> > I turned on trace options for OSPF, but couldn't
> > really extract the info I need.
> >
> > TIA for any pointers.
> > ---andrew
> >
> > __________________________________________________
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>
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>
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