[Boatanchors] A Tube Puzzle

[Bruce Long]

51=5+1 = 6?



________________________________
 From: J. Forster <jfor at quikus.com>
To: Milsurplus at mailman.qth.net; arc5 at mailman.qth.net; armyradios at yahoogroups.com 
Cc: boatanchors at puck.nether.net; Vintage-Military-RADAR at yahoogroups.com 
Sent: Monday, April 30, 2012 2:02 PM
Subject: [Boatanchors] A Tube Puzzle
 
Hi,

My understanding was that standard tube conventions had the leading
digit(s) as the filament voltage:

1B3   = 1 V
2X2   = 2 V
5Y3   = 5 V
6X5   = 6 V
12AX7 = 12 V
35W4  = 35 V
50C5  = 50 V
117L7 = 117 V

etc.

How does a 2C51W dual triode fit in? It has a 6 V filament?

-John

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